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suppose the length of a rectangle is 2x + 1 and the width is 3x-2 . find the value of x if the perimeter is equal to 38 inches
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2L + 2W = 38, or
2*(2x+1) + 2*(3x-2) = 38, --->
4x + 2 + 6x - 4 = 38,
10x - 2 = 38 ---> 10x = 38 + 2 ---> 10x = 40 ---> x = 40/10 = 4.
Answer. x = 4.
The length = 2x+1 = 9. The width = 3x-2 = 10.
The width is longer than the length.
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