SOLUTION: How to I do this? I know the answers are 10,11,12 but I have no idea where to start. Find thee consecutive integers, the sum of whose squares is 65 more than three times the squ

Algebra ->  Square-cubic-other-roots -> SOLUTION: How to I do this? I know the answers are 10,11,12 but I have no idea where to start. Find thee consecutive integers, the sum of whose squares is 65 more than three times the squ      Log On


   

Question 1045625: How to I do this? I know the answers are 10,11,12 but I have no idea where to start.
Find thee consecutive integers, the sum of whose squares is 65 more than three times the square of the smallest.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The integers are system%28n%2Cn%2B1%2Cn%2B2%29.

Sum of their squares, n%5E2%2B%28n%2B1%29%5E2%2B%28n%2B2%29%5E2

Sixty-five more than three times square of the smallest,65%2B3n%5E2

Put it all together....,