Question 104549: A total of $8000 is invested, part at 6% and the remainder at 9%. How much is invested at each rate if the annual interest is $540? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! .09X+.06(8000-X)=540
.09X+480-.06X=540
.03X=540-480
.03X=60
X=60/.03
X=2000 INVESTED @ 9%
8000-2000=6000 INVESTED @ 6%.
PROOF
.09*2000+.06*6000=540
180+360=540
540=540