SOLUTION: Answer must be in radians. Thanks! 2sin^2x + 3sinx-2 =0 I factored it and was left with (2sinx-1) (sinx+2) I set it =0 and now have sin(y) =1/2. My homework has the answers on

Algebra ->  Trigonometry-basics -> SOLUTION: Answer must be in radians. Thanks! 2sin^2x + 3sinx-2 =0 I factored it and was left with (2sinx-1) (sinx+2) I set it =0 and now have sin(y) =1/2. My homework has the answers on      Log On


   



Question 1045452: Answer must be in radians. Thanks!
2sin^2x + 3sinx-2 =0
I factored it and was left with (2sinx-1) (sinx+2)
I set it =0 and now have sin(y) =1/2.
My homework has the answers on the back so we need to show our work.
But the answers are 7pi/6 ,11pi/6 which have -1/2 as their y cord
What did I do wrong since I have a positive 1/2?

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
Answer must be in radians. Thanks!
2sin^2x + 3sinx-2 =0
I factored it and was left with (2sinx-1) (sinx+2)
I set it =0 and now have sin(y) =1/2.
My homework has the answers on the back so we need to show our work.
But the answers are 7pi/6 ,11pi/6 which have -1/2 as their y cord
What did I do wrong since I have a positive 1/2?
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2sin^2x + 3sinx-2 =0 --->  Factor !  --->

(2sinx-1)*(sinx+2) = 0

The equation deploys in two independent equations:


1.  2sin(x) - 1 = 0  --->  2sin(x) = 1  --->  sin(x) = 1%2F2  --->  x = pi%2F6  and/or  x = 5pi%2F6.


2.  sinx+2 = 0  --->  sin(x) = -2.  --->   this equation has no solutions.


Answer.  The solutions are x = pi%2F6  and/or  x = 5pi%2F6.


Do not start your writing saying "Answer must be in radians."

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