SOLUTION: Explain me how to do this problem. m < OZP = 4r+2, m < PZQ = 5r-12, and m < OZQ = 125. What are m < OZP and m

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Question 1045449: Explain me how to do this problem.
m < OZP = 4r+2, m < PZQ = 5r-12, and m < OZQ = 125.
What are m < OZP and m < PZQ?

Found 3 solutions by Alan3354, ikleyn, jim_thompson5910:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website!
Not sufficient info.

Answer by ikleyn(52787)   (Show Source):
You can put this solution on YOUR website!
.
m(< OZP) = 4r+2, m(< PZQ) = 5r-12, and m(< OZQ) = 125.
What are m(< OZP) and m(< PZQ)?
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You failed to explain what are these angles // the parts of what figure they are.

You know it, but we don't know.

Re-edit and re-post.

Also be careful using the symbol "<".
It requires blank symbol after itself, otherwise it suppresses the text after it.

Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website!
angle OZP and angle PZQ combine to angle OZQ (this can be seen if you draw out the figure or use the figure given to you in the book)

So this means

(measure of angle OZP)+(measure of angle PZQ)=(measure of angle OZQ)

(m < OZP)+(m < PZQ)=(m < OZQ)

(4r+2)+(5r-12)=(125)

4r+2+5r-12=125

9r-10=125

9r-10+10=125+10

9r+0=135

9r=135

9r/9=135/9

r = 15

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Now that we know that the value of r is r = 15, we can use this to find the angles

m < OZP = 4r+2
m < OZP = 4*15+2
m < OZP = 60+2
m < OZP = 62

m < PZQ = 5r - 12
m < PZQ = 5*15 - 12
m < PZQ = 75 - 12
m < PZQ = 63

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Summary:
m < OZP = 62
m < PZQ = 63

SOLUTION: Explain me how to do this problem. m < OZP = 4r+2, m < PZQ = 5r-12, and m < OZQ = 125. What are m < OZP and m < PZQ?