SOLUTION: The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference
of their ages will be:
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of their ages will be:
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Question 1045432: The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference
of their ages will be: Found 2 solutions by Alan3354, jorel555:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The age of Radhika's mother is square the age of Radhika. Five years hence, mother will be 3 times her age. The difference
of their ages will be:
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M = R^2
M+5 = 3(R+5)
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Sub for M
R^2+5 = 3R+15
R^2 - 3R - 10 = 0
(R-5)*(R+2) = 0
R = 5
etc
You can put this solution on YOUR website! Let r represent Radhika. Then Radhika's mother is rē. So
3(r+5)=rē+5
3r+15=rē+5
rē-3r-10=0
(r+2)(r-5)=0
r=5
r+5=10
rē+5=30
In 5 years, the difference in their ages will be 20 years.☺☺☺☺
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