SOLUTION: The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?

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Question 1045417: The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?
Found 3 solutions by josgarithmetic, advanced_Learner, MathTherapy:
Answer by josgarithmetic(39625) About Me  (Show Source):
Answer by advanced_Learner(501) About Me  (Show Source):
Answer by MathTherapy(10555) About Me  (Show Source):
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The sum of three consecutive numbers is 41 less than five times the largest number. What is the largest number?
Let largest number be L

Then smallest and middle are: L - 2, and L - 1, respectively

We then get: L - 2 + L - 1 + L = 5L - 41

3L - 3 = 5L - 41

3L - 5L = - 41 + 3

- 2L = - 38

L, or largest = %28-+38%29%2F%28-+2%29 = highlight_green%2819%29