SOLUTION: X P(X) 1 .051 2 .099 3 .093 4 .635 5 .122 Suppose a movie is selected randomly from this group. a. Find the proba

Algebra ->  Probability-and-statistics -> SOLUTION: X P(X) 1 .051 2 .099 3 .093 4 .635 5 .122 Suppose a movie is selected randomly from this group. a. Find the proba      Log On


   



Question 1045413: X P(X)
1 .051
2 .099
3 .093
4 .635
5 .122
Suppose a movie is selected randomly from this group.
a. Find the probability the book received a rating of at least 2.
b. Find the probability that the book got a rating higher than 3
c. Find the probability that the book received a rating of 3 or higher.
d. What is the average rating of the movie in this group?

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
X P(X)
1 .051
2 .099
3 .093
4 .635
5 .122
Suppose a movie is selected randomly from this group.
Note: Your Common Sense can be very helpful in Probability

a. Find the probability the book received a rating of at least 2.
P(x <= 2) = .051 + .099 CS answer
b. Find the probability that the book got a rating higher than 3
P(x> 3) = .635 +.122 CS answer
c. Find the probability that the book received a rating of 3 or higher.
P(x >= 3) = .093 + .635 +.122 CS answer
d. What is the average rating of the movie in this group?
This is a "weighted average" depending on the probability of the different ratings
Weighted Average = Σ xP(x) / ΣP(x)
[1(.051) + 2(.099) + 3(.093) + 4(.635) + 5(.122)