SOLUTION: A telephone company offers customers two payment plans for monthly service. Plan A costs $5 per month plus $0.10 per minute for calls. Plan B cost $8 per month plus $0.07 minute fo

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Question 1045367: A telephone company offers customers two payment plans for monthly service. Plan A costs $5 per month plus $0.10 per minute for calls. Plan B cost $8 per month plus $0.07 minute for calls. 1. Write an equation for each plan. Are these equations in standard form or Slope-intercept form?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
let x equal the number of minutes.
let y equal the total cost.

total cost for the first plan is y = 5 + .10 * x

total cost for the second plan is y = 8 + .07 * x

these equations are in slope intercept form after you re-order the terms in descending order of degree, which is y = mx + b.

reorder the terms of each equation and you get:

y = .10 * x + 5
y = .07 * x + 8

that's slope intercept form.

m is the slope and b is the y-intercept.

in the first equation, the slope is .10 and the y-intercept is 5.

in the second equation, the slope is .07 and he y-intercept is 8.

the y-intercept is the value of y when x = 0.

the slope is the change in the value of y divided by the change in the value of x.

the formula for that is m = (y2-y1) / (x2-x1).

(x1,y1) and (x2,y2) are any two different points on the line of each equation.

your graph will look like this.

$$$

the blue line is y = .07x + 8.
the red line is y = .10x + 5.

from the graph, you can see that the plans break even when x = 100 and y = 15.

y = 5 + .10 * x becomes y = 5 + .10 * 100 becomes y = 5 + 10 becomes y = 15.

y = 8 + .07 * x becomes y = 8 + .07 * 100 becomes y = 8 + 7 becomes y = 15.

slope intercept form is y = mx + b
m is the slope and b is the y-intercept.

standard form is ax + by = c
a is the coefficient of the x term.
b is the coefficient of the y term.
c is the constant term.

a must be positive.
a,b, and c must be integers.

that's the strict definition.

conversion from slope intercept form to standard form would proceed as follows for the equation of y = 5 + .10 * x

subtract .10 * x from both sides of the equation to get:

-.10 * x + y = 5

multiply both sides of the equation by -1 to get:

.10 * x - y = -5

multiply both sides of the equation by 10 to get:

x - 10y = -50

by convention, the standard form of the equation has a positive coefficient for the x term and the coefficients of the x term and the y term and the constant term are integers.

here's a reference.

http://www.algebra-class.com/writing-equations-2.html

your other equation would be converted to standard equation as follows:

start with y = .07 * x + 8

subtract .07 * x from both sides of the equation to get:

-.07 * x + y = 8

multiply both sides of the equation by -100 to get:

7x - 100y = -800

your 2 equations in standard form are:

x - 10y = -50
7x - 100y = -800

you convert these to slope intercept form by solving for y and then re-ordering the terms in descending order of degree.

start with x - 10y = -50
subtract x from both sides of the equation to get -10y = -x - 50
divide both sides of the equation by -10 to get y = -1/-10 * x - 50/-10
simplify to get y = .10 * x + 5.

start with 7x - 100y = -800
subtract 7x from both sides of the equation to get -100y = -7x - 800
divide both sides of the equation by -100 to get y = -7/-100 * x -800/-100
simplify to get y = .07x + 8