SOLUTION: Prove that: Sin^4x =1÷8 (3-4cos2x+cos4x)

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Question 1045299: Prove that:
Sin^4x =1÷8 (3-4cos2x+cos4x)
Found 2 solutions by advanced_Learner, Alan3354:
Answer by advanced_Learner(501) About Me  (Show Source):
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Prove that:
Sin^4x =1÷8 (3-4cos2x+cos4x)
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At x = 0:
0 = 1/(8*(3 - 4*1 + 1))
0 = 1/(8*0)
0 = 1/0
Not an identity.