SOLUTION: I dont understand how to do this type of problem where i have to find asymptotes, someone please help!!! Thanks!!! The problem is: Graph the function {{{f(x)=(2x)/(x+2)}}}. Find as

Algebra ->  Rational-functions -> SOLUTION: I dont understand how to do this type of problem where i have to find asymptotes, someone please help!!! Thanks!!! The problem is: Graph the function {{{f(x)=(2x)/(x+2)}}}. Find as      Log On


   

Question 104526: I dont understand how to do this type of problem where i have to find asymptotes, someone please help!!! Thanks!!! The problem is: Graph the function f%28x%29=%282x%29%2F%28x%2B2%29. Find asymptotes and intercepts.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%282x%29%2F%28x%2B2%29
verticle assymptote: Check the denominator. What value for x makes the denominator zero? Ans. x=2. That is the verticle assymptote where division by zero is not allowed.
horizontal assymptote: m is the degree of the polynomial denominator. n is the degree of the polynomial numerator.
for m for m=n the h.a. is the line a[m]/b[n]
for m>n there is no h.a.
.
for m=n the h.a. is the line a[m]/b[n] is our case. 2x/x=2 so y=2 is the verticle assymptote.
.
x intercept when y=0: 2x/(x+2)=0...x=0
intercept when x=0: 0/2=0...y=0
.
Hope that helps.
Ed