SOLUTION: The stopping distance of a car varies directly with square of the car speed. A car traveling at 65 mph requires 212 feet to stop? What distance would be required to stop if the sam
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-> SOLUTION: The stopping distance of a car varies directly with square of the car speed. A car traveling at 65 mph requires 212 feet to stop? What distance would be required to stop if the sam
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Question 1045245: The stopping distance of a car varies directly with square of the car speed. A car traveling at 65 mph requires 212 feet to stop? What distance would be required to stop if the same car is traveling 80mph? Give answer to nearest tenth of a foot. Found 2 solutions by Boreal, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Distance=k*speed^2
212=k*65^2
k=212/4325=0.0490 without rounding
D=k*80^2=313.71 or 313.7 feet.
You can put this solution on YOUR website! The stopping distance of a car varies directly with square of the car speed.
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--> d = k*v^2
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A car traveling at 65 mph requires 212 feet to stop?
Is that a question?
212 = k*65^2
k = 212/4225
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What distance would be required to stop if the same car is traveling 80mph? Give answer to nearest tenth of a foot.
d = k*v^2
d = (212/4225)*80^2
d =~ 321.1 feet
