SOLUTION: The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 more than the age of son. Find their present ages?
Algebra ->
Customizable Word Problem Solvers
-> Age
-> SOLUTION: The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 more than the age of son. Find their present ages?
Log On
Question 1045214: The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 more than the age of son. Find their present ages? Answer by advanced_Learner(501) (Show Source):
You can put this solution on YOUR website! The age of a father is 5 more the age of 6 times the age of his son. 7 years after, the age of the father becomes 3 times the age of son. Find their present ages?
let x be son age
father age is 6x+5
after 7 years
x+7
6x+12
6x+12=(x+7)*3
x=3
