SOLUTION: 2 men and 5 boys can do a piece of work in 4 days, while 4 men and 4 boys can do it in 3 days how long would it take one man alone to do it and how many days would it take one boy
Question 1045208: 2 men and 5 boys can do a piece of work in 4 days, while 4 men and 4 boys can do it in 3 days how long would it take one man alone to do it and how many days would it take one boy alone to do it? Found 3 solutions by josgarithmetic, ikleyn, MathTherapy:Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Alternative method is assign variables for each type of person's rate in units of JOB/DAYS, and this gives linear equations.
x for one-boy rate
y for one-man rate
Elimination Method should be more comfortable to use for solving the system.
Multiply first equation by 3, and multiply second equation by 2.
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Subtract second equation from first equation, member by member.
Remember, here the unit of work rate is , so this rate for ONE BOY means "ONE JOB done in 36 DAYS".
You can use the same method for eliminating the x; but here, the best choice is return to , but multiply first equation by 3; and multiply second equation by 5.
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You do it......
You can put this solution on YOUR website! 2 men and 5 boys can do a piece of work in 4 days, while 4 men and 4 boys can do it in 3 days how long would it take one man alone to do it and how many days would it take one boy alone to do it?
Isn't this the same as: Linear_Equations_And_Systems_Word_Problems/1045207?
Why did you post it twice? Oh, I see. Maybe because you got an answer that was nowhere near the correct one. Okay!
The correct answer is there now, so you can revisit that problem.