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Question 1045202:  Hello, I need help with my assignment. Can you help me please? 
1.Graph the relation represented by y = x^2 + 1. 
2.Find the domain and range. 
Also could you explain how to get all the domain and range because in tutorials I could only see them getting only one. Thank you for the help! 
 
 Answer by Theo(13342)      (Show Source): 
You can  put this solution on YOUR website! here's the graph.
 
 
 
 
 
the domain is all real values of x.
 
 
the range is all real values of y >= 1.
 
 
you can't see it on the graph because the values of x extend all the way to plus and minus infinity.
 
 
similarly, the values of y extend all the way to plus infinity.
 
 
a simple test is to take a very high value of x and a vary low value of x, such as plus or minus 1000000.
 
 
use your calculator to find the value of y when y = x^2 + 1.
 
 
for 1000000, the value of y will be 1 * 10^12 based on what the calculator can show.
 
 
for -1000000, the value of y will be 1 * 10^12 again.
 
 
you made x very very large in a negative and positive direction and the value of y became very very large in a positive direction.
 
 
all values of x are in the domain because there is no value of x that's not real.
 
 
based on the equation, y can be any value of y that's positive and greaer than or equal to 1.
 
 
when x = 0, y = 1
 
 
y is positive when x gets greater than 0 in a positive or negative direction.
 
 
here's a tutorial that might help.
 
 
if you have any more questions on this topic, or have another specific problem regarding it that you are struggling with, send me an email.
 
 
http://www.intmath.com/functions-and-graphs/2a-domain-and-range.php
 
 
be aware that most of the time they are talking about functions, which are subsets of equation.
 
 
if there is only value of y for each and every value of x, then you have a function.
 
 
if there can be more than one value of y for any value of x, then you have a relation.
 
 
the equation you gave me is a function.
 
 
here's a graph of an equation that is a rerlation and not a function.
 
 
the equation is y^2 = x
 
 
solve for y in that equation and you will get y = plus or minus square root of (x).
 
 
the domain is all real values of x that are greater than or equal to 0.
 
 
those values of x will create real values of y.
 
 
negative values of x will not create real values of y because the square root of a negative number is not real.
 
 
here's the graph:
 
 
 
 
 
 
the domain is all real value of x >= 0.
 
 
the range is all real values of y.
 
 
you can see that the graph doesn't show anything for any values of x < 0.
 
 
this is because the graph will only show the real values of y.
 
 
any value of x > 0 will result in a real value of plus or minus y.
 
 
this equaton is not a function because there are more than one possible value of y for any one distinct value of x.
 
 
for erxample, when x = 4, y = plus or minus 2. 
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