SOLUTION: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mike’s bus was in heavy traffic and had to travel 20 miles per hour slower than Adam’
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mike’s bus was in heavy traffic and had to travel 20 miles per hour slower than Adam’
Log On
Question 1045092: Mike and Adam left a bus terminal at the same time and traveled in opposite directions. Mike’s bus was in heavy traffic and had to travel 20 miles per hour slower than Adam’s bus. After 3 hours, their buses were 270 miles apart. How fast was each bus going? Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = the speed of Adam's bus in mi/hr = the speed of Mike's bus in mi/hr
----------------------------------------
Since they are travelling in opposite directions, you
can think of this as one of them standing still and
the other covering the miles at the sum
of their speeds
---------------------
and
------------------------
Adam's speed is 55 mi/hr
Mike's speed is 35 mi/hr
------------------------
check answer:
Adam's equation: mi
-----------------
Mike's equation: mi
-----------------
OK
