Question 1044926: Steve has $2.05 in quarters and nickels. He has 13 coins altogether. How many coins of each kind does he have? Answer by ikleyn(52847) (Show Source):
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Steve has $2.05 in quarters and nickels. He has 13 coins altogether. How many coins of each kind does he have?
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Let "n" be the number of nickels Steve has in his collection.
Then the number of quarters is 13 - n.
The nickels contribute 5n cents to the total.
The quarters contribute 25*(13-n).
Altogether they make 5n + 25*(13-n) cents.
It is equal to 205 cents, according to the condition.
It gives you an equation
5n + 25*(13-n) = 205.
Simplify and solve it for n:
5n + 325 - 25n = 205.
-20n = 205 - 325,
-20n = -120,
n = = 6.
Answer. 6 nickels and 13-6 = 7 quarters.
