SOLUTION: Steve has $2.05 in quarters and nickels. He has 13 coins altogether. How many coins of each kind does he have?

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Question 1044926: Steve has $2.05 in quarters and nickels. He has 13 coins altogether. How many coins of each kind does he have?
Answer by ikleyn(52824) About Me  (Show Source):
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Steve has $2.05 in quarters and nickels. He has 13 coins altogether. How many coins of each kind does he have?
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Let "n" be the number of nickels Steve has in his collection.
Then the number of quarters is 13 - n.

The nickels contribute 5n cents to the total.
The quarters contribute 25*(13-n).
Altogether they make 5n + 25*(13-n) cents.

It is equal to 205 cents, according to the condition.

It gives you an equation

5n + 25*(13-n) = 205.

Simplify and solve it for n:

5n + 325 - 25n = 205.

-20n = 205 - 325,

-20n = -120,

n = %28-120%29%2F%28-20%29 = 6.

Answer. 6 nickels and 13-6 = 7 quarters.

For many other solved coin problems see the lessons
    - Coin problems
    - More Coin problems
    - Solving coin problems without using equations
    - Kevin and Randy Muise have a jar containing coins
    - Typical coin problems from the archive
in this site.