SOLUTION: Asking this question again as was responded too but no answer was given: Need to find the surface area of composite figures and leave answer in terms of pi. The first figure is

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Question 1044876: Asking this question again as was responded too but no answer was given:
Need to find the surface area of composite figures and leave answer in terms of pi. The first figure is a cone with a radius of 10mm and a height of 24mm (does not give the slant height) and inside is a hemisphere with a radius of 8mm.

Found 2 solutions by Edwin McCravy, KMST:
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

The reason there was no answer is because of the words
"and inside is a hemisphere with a radius of 8mm."
Surface area problems are always about "outside" things 
only, and never involve "inside" things.

Edwin

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
In a right circular cone, the base radius, r is perpendicular to the height, h .
Radius, height, and slant height form a right triangle,
and the slant height can be calculated using the Pythagorean theorem as
sqrt%28h%5E2%2Br%5E2%29 .
So, when given r and h , the lateral surface area of a right circular cone can be calculated as
pi%2Ar%2Asqrt%28h%5E2%2Br%5E2%29 .
With h=24 and r=10 ,
the slant height is sqrt%2824%5E2%2B10%5E2%29=26 ,
and the lateral surface area is pi%2A10%2A26=260pi .

I assume that your composite figure is a cone with a hemisphere taken out of the base, so that the cross section looks like this:
, and only a ring is left of the base of the cone,like this: .

The surface area of that ring that is left over of the base of the cone
is the area of a circle of radius 10
minus the area of a circle of radius 8 ;
pi%2A10%5E2-pi%2A8%5E2=100pi-64pi=36pi .

The surface area of a sphere of radius r=8 is 4%2Api%2A8%5E2 ,
so the surface of a hemisphere of radius 8 is
2%2Api%2A8%5E2=2%2Api%2A64=128pi ,

The surface area of your composite figure is mad of three parts:
lateral surface area of the cone =260pi ,
area of ring on the cone base =36pi , and
area of hemisphere =128pi .
Total surface area =260pi%2B36pi%2B128pi=highlight%28424pi%29 .