Question 1044815: In a random sample of 23 people, the mean commute time to work was 34.4 minutes and the standard deviation was 7.1 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ. What is the margin of error of μ?
Interpret the results.
The confidence interval for the population mean μ is?(Round to one decimal place as needed.)
The margin of error of μ is? (Round to one decimal place as needed.)
Interpret the results.
A.With 98% confidence, it can be said that the population mean commute time is between the bounds of the confidence interval.
B.It can be said that 98% of people have a commute time between the bounds of the confidence interval.
C.If a large sample of people are taken approximately 98% of them will have commute times between the bounds of the confidence interval.
D.With 98% confidence, it can be said that the commute time is between the bounds of the confidence interval.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 98% CI is mean +/- t(0.99, df=22)s/sqrt(n)
34.4+/- 2.508*7.1/sqrt(23); the second part equals 3.7
(30.7,38.1)
The margin of error is +/-3.7
The best answer is A, because it deals with population mean commute time, which is a more precise statement than the commute time. It is not a probabilistic statement, so B and C are eliminated.
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