SOLUTION: What is the gradient of the straight line represented by the following equation? u = 64.9t - 660 (11 ≤ t ≤ 14)

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Question 1044789: What is the gradient of the straight line represented by the following equation?
u = 64.9t - 660 (11 ≤ t ≤ 14)
Found 2 solutions by Alan3354, Cromlix:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Gradient of a straight line = m
Equation of a straight line =
y = mx + c
Relating it to your equation I
would assume that the 64.9 was the
gradient and the y intercept = -660.
Hope this helps :-)