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Find by calculating the centre of a circle whose centre is on the line 7y=-2x +36 and touches both the positive x-axis and positive y-axis
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Since the circle touches the both axes, its center lies on the bisector of the QI, which is a straght line y = x.
So, the center lies in the intersection of the two straight lines:
7y = -2x + 36, and
y = x.
Substitute y = x into the first equation, and you will get
7y = -2y + 36, or 9y = 36, or y = 4.
Then x = 4, too.
Answer. The center lies at the point (4,4).