SOLUTION: An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. Find:
a.) its position and velocity after 8 sec
b.) the time requi
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-> SOLUTION: An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. Find:
a.) its position and velocity after 8 sec
b.) the time requi
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Question 1044693: An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal. Find:
a.) its position and velocity after 8 sec
b.) the time required to reach its maximum height
c.) The horizontal distance Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An artillery shell is fired with an initial velocity of 100 m/s at an angle of 30 degrees above the horizontal.
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Using 10 m/sec/sec as gravity:
Find:
a.) its position and velocity after 8 sec
The horizontal component = 100*cos(30) =~ 86.6 m/sec
The vertical component = 100*sin(30) = 50 m/sec
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h(t) = -5t^2 + 50t
h(8) = 80 meter AGL (height)
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The horizontal distance from the muzzle = 8*86.6 = 692.8 meters
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Horizontal speed is constant = 86.6 m/sec
Vertical speed = 50 - 10t = -30 m/sec (descending)
Its speed is the vector sum:
= sqrt(86.6^2 + 30^2) =~ 91.65 m/sec
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b.) the time required to reach its maximum height
50/10 = 5 seconds
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c.) The horizontal distance
Flight time = 10 seconds
H distance = 86.6*10 = 866 meters
