SOLUTION: Solve for x on the interval [0,2pi) 2sin(2pi)-sqr(3)=0 I recently asked this question, but the interval was wrong. The correct interval is this one, [0,2pi).

Algebra ->  Trigonometry-basics -> SOLUTION: Solve for x on the interval [0,2pi) 2sin(2pi)-sqr(3)=0 I recently asked this question, but the interval was wrong. The correct interval is this one, [0,2pi).      Log On


   



Question 1044673: Solve for x on the interval [0,2pi)
2sin(2pi)-sqr(3)=0
I recently asked this question, but the interval was wrong. The correct interval is this one, [0,2pi).

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
Solve for x on the interval [0,2pi)
2sin(2pi)-sqr(3)=0
I recently asked this question, but the interval was wrong. The correct interval is this one, [0,2pi).
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Read it and try to understand why.

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