SOLUTION: solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help
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-> SOLUTION: solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help
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Question 1044657: solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help me please? Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
solve for x on the interval [0,2pi)
3cosx-1=2
first i isolated cosx and got cosx=1
i did cos^-1(1) to find x and got 0 but i am being told that 0 is not the correct answer. help me please?
~~~~~~~~~~~~~~~~~~~~~~~~~
3cos(x) - 1 = 2 --->
3cos(x) = 2 + 1 ---> 3cos(x) = 3 ---> cos(x) = 1 ---> x = 0 (zero).
The only solution is x = 0 (zero).
There is no other solutions.
0 (zero) IS CORRECT ANSWER.
