SOLUTION: Please show me how to solve : n + 3 over 5 = n - 1 over 2

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Question 1044647: Please show me how to solve : n + 3 over 5 = n - 1 over 2
Found 2 solutions by ikleyn, solver91311:
Answer by ikleyn(52782) About Me  (Show Source):
You can put this solution on YOUR website!
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Please show me how to solve : n + 3 over 5 = n - 1 over 2
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%28n%2B3%29%2F5 = %28n-1%29%2F2.

Multiply both sides by 10 (which is the Least Common Denominator) to rid of the denominators. You will get

2*(n+3) = 5*(n-1).

Simplify:

2n + 6 = 5n - 5,

6 + 5 = 5n - 2n,

11 = 3n,

n = 11%2F3.

Check.  %28n%2B3%29%2F5 = %28%2811%2F3+%2B+3%29%29%2F5 = %28%2811%2F3+%2B+9%2F3%29%29%2F5 = 20%2F%285%2A3%29 = 20%2F15 = 4%2F3.

%28n-1%29%2F2 = %28%2811%2F3-1%29%29%2F2 = %28%2811%2F3-3%2F3%29%29%2F2 = %28%288%2F3%29%29%2F2 = 8%2F%283%2A2%29 = 4%2F3.   OK, correct.

Answer.  n = 11%2F3.


Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Multiply both sides of the equation by 10. Then solve the resulting single variable linear equation for .

John

My calculator said it, I believe it, that settles it