SOLUTION: the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?

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Question 1044636: the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B6x%2By%5E2-4y=-3

Complete The Square for the x and the y. Keep going, putting into standard form, and read the desired values. You need to use the terms, 9 for the x and 4 for the y.

Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
the radius (R) and the center (C) of this circle x^2+y^2+6x-4y+3=0 are ?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

Complete the square separately in "x" and "y":

x%5E2%2By%5E2%2B6x-4y%2B3 = 0   --->

(x%5E2%2B6x + __) - __ + (y%5E2-4y + __) - __ + 3 = 0,

%28x%5E2+%2B6x+%2B9%29+-+9+%2B%28y%5E2-4y%2B4%29+-+4+%2B+3 = 0,

%28x%2B3%29%5E2+-9+%2B+%28y-2%29%5E2+-+4+%2B+3 = 0,

%28x%2B3%29%5E2+%2B+%28y-2%29%5E2 = 9 + 4 - 3,

%28x%2B3%29%5E2+%2B+%28y-2%29%5E2 = 10.

The circle with the center at  (-3,2)  of the radius  sqrt%2810%29.