SOLUTION: When Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average

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Question 1044619: When Fritz drives to work his trip takes 36 ​minutes, but when he takes the train it takes 20 minutes. Find the distance Fritz travels to work if the train travels an average of 48 miles per hour faster than his driving. Assume that the train travels the same distance as the car.
Found 2 solutions by josgarithmetic, jorel555:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
36 minutes is 36%2F60=9%2F15=%283%2F5%29hour.

20 minutes is %281%2F3%29hour.

Travel Rates Rule to relate rate, time, distance, is RT=D. 
            SPEED       TIME       DISTANCE

CAR          r          3%2F5        d

TRAIN      r+48         1%2F3        d


r%283%2F5%29=%281%2F3%29%28r%2B48%29, solve this for r, and use it to find d.

Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let Fritz's rate be n. 36 minutes is 3/5 hr; 20 minutes equals 1/3 hour. So:
3/5n=1/3(n+48)
3/5n=1/3n+16
4/15n=16
n=60
3/5x60=36 miles to work. ☺☺☺☺