Question 1044596: Solve (7x-3y)^2 - 7(7x-3y)+ 10 =0
and 2x-y=1.Find the solution of the equation by step by step. Found 2 solutions by rothauserc, MathTherapy:Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! 2x - y = 1
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y = 2x - 1
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substitute for y in first equation
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(7x-3(2x-1))^2 -7(7x-3(2x-1))^2 +10 = 0
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(7x-6x+3)^2 -7(7x-6x+3)^2 +10 = 0
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(x+3)^2 -7(x+3)^2 +10 = 0
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6(x+3)^2 = 10
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(x+3)^2 = 5/3
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x+3 = square root(5/3)
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x = square root(5/3) -3
x = -square root(5/3) - 3
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y = 2(square root(5/3) -3) + 1 = 2square root(5/3) -5
y = 2(-square root(5/3) -3) + 1 = -2square root(5/3) -5
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We have two sets of solutions
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x = square root(5/3) -3
y = 2square root(5/3) -5
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x = -square root(5/3) - 3
y = -2square root(5/3) -5
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