Use the formulas for the derivative of ln(u),
are the formulas the derivative of uv and ln(u)
on the right:
Multiply both sides by y
Substitute for y on the right using the ORIGINAL equation
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Square both sides:
Substitute for y on the right using the ORIGINAL equation
That's the answer, but you were instructed to use
natural logs. So let's do it using natural logs:
Change the square root to the 1/2 power:
Multiply both sides by y
Substitute for y on the right using the ORIGINAL equation
This is the same as the the answer we got when we did
it by squaring both sides, but this way the denominator
came out rationalized. The two answers are equivalent.
Edwin