SOLUTION: The qoutient of dividing 4 times the cube of a number by the sum of the square of the number and 3

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Question 1044448: The qoutient of dividing 4 times the cube of a number by the sum of the square of the number and 3
Found 2 solutions by Boreal, MathLover1:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
4x^3/(x^2+3)
=====4x
x^2+3/4x^3
=====4x^3+12x
change signs and subtract
========-12x,
remainder is -12x/(x^2+3)
4x -12x/(x^2+3).
Check by multiplying quotient by divisor
4x(x^2+3)-12x=4x^3.



Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let number be x
The qoutient of dividing
4 times the cube of a number (which is x%5E3): 4x%5E3
by the sum of the square of the number (which is x%5E2)and 3:x%5E2%2B3)
so, the quotient is:4x%5E3%2F%28x%5E2%2B3%29