SOLUTION: The pressure of an ideal gas was held constant. The initial temperature and volume were 600 K and 500 ml respectively. What would the final temperature be if the volume were increa

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Question 1044097: The pressure of an ideal gas was held constant. The initial temperature and volume were 600 K and 500 ml respectively. What would the final temperature be if the volume were increased to 1500 ml?
Found 2 solutions by jorel555, ikleyn:
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Since pressure x volume remains constant, then:
600 x 500=300000
300000/1500=200 K as the final temperature. ☺☺☺☺

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
The pressure of an ideal gas was held constant. The initial temperature and volume were 600 K and 500 ml respectively.
What would the final temperature be if the volume were increased to 1500 ml?
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Apply the "Ideal gas Law".

See this Wikipedia article

   The ideal gas law is the equation of state of a hypothetical ideal gas. 
   It is a good approximation of the behavior of many gases under many conditions, although it has several limitations. 
   It was first stated by Émile Clapeyron in 1834 as a combination of the empirical Boyle's law, Charles' law and Avogadro's Law.
   The ideal gas law is often written as:

   PV = nRT

   where:

   P is the pressure of the gas,
   V is the volume of the gas,
   n is the amount of substance of gas (in moles),
   R is the ideal, or universal, gas constant, equal to the product of the Boltzmann constant and the Avogadro constant,
   T is the absolute temperature of the gas.

For two states of your gas

PV%5B1%5D = nRT%5B1%5D   and 

PV%5B2%5D = nRT%5B2%5D.

Now divide left sides and right sides. You will get

V%5B1%5D%2FV%5B2%5D = T%5B1%5D%2FT%5B2%5D.

Hence, T%5B2%5D = T%5B1%5D%2A%28V%5B1%5D%2FV%5B2%5D%29 = 600%2A%28500%2F1500%29 = 200 K.