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Question 1043957: Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph.She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
Found 2 solutions by Alan3354, ikleyn:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph.She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
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She spends 4 hours driving.
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Avg speed for the round trip = 2*80*60/(80+60) = 480/7 km/hr
RT distance = 4*480/7 km
Each way = 960/7 kms
Answer by ikleyn(52775)  (Show Source):
You can put this solution on YOUR website! .
Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph. She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Amacha spent driving 7 hours - 3 hours = 4 hours.
Led D be the distance between the offices.
Then you have this equation for the unknown D
 = 4, (1)
where 4 = 4 hours is the total driving time.
To solve (1), multiply both sides by the Least Common Denominator 240. You will have
3D + 4D = 4*240, or 7D = 960.
Hence, D =  = 137.14 miles.
Solved.
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