Since D is the midpoint of BC, AD must be a perpendicular bisector of BC. Then angles ADB and ADC are right angles. Then triangles ADB and ADC are isosceles right triangles because AD = BD = CD. The acute angles of an isosceles right triangle measure 45 degrees. The angle measure you seek is then the sum of two 45 degree angles, that is the measure of angle BAC is 90 degrees.
To avoid confusion in the future, ask to find the MEASURE of an angle. Otherwise, I could correctly point to a diagram and say, "It's right there".
John
My calculator said it, I believe it, that settles it