SOLUTION: Divide f(x)=3x^4+2x^3-x^2-x-6 by p(x)=x-1

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Question 1043852: Divide f(x)=3x^4+2x^3-x^2-x-6 by p(x)=x-1
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
You can use either polynomial division or synthetic division. Synthetic division will be faster. Here is the work as polynomial division: 
            3x^3    5x^2     3x     2
      ___________________________________________
x-1   |     3x^4    2x^3    -x^2    -x    -6
      |
      |     3x^4   -3x^3
      |_____________________
             0      5x^3
                    5x^3   -5x^2
                  _______________
                     0     3x^2
                           3x^2   -3x
                          ___________
                           0      2x
                                  2x    -2
                                  _________
                                   0    -4

Notice remainder is -4.

Quotient fully is 3x%5E3%2B5x%5E2%2B3x%2B2-4%2F%28x-1%29.

Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

Divide f(x)=3x^4+2x^3-x^2-x-6 by p(x)=x-1
Correct answer: highlight_green%283x%5E3+%2B+5x%5E2+%2B+4x+%2B+3+%2B+-3%2F%28x+-+1%29%29