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Question 1043814: Janene and Emily plan to go on a marathon rn. Emily arrived late, So janene starts running 16 minutes before Emily. Janene runs at an average rate of 9 minutes per mile, and emily runs at the average rate of 8.25 minutes per mile. If they both start at the same location, how many minutes will it take for Emily to catch up to Janene?
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! Let x=the number of minutes they run until they have run the same distance.
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Janine (16/9) miles + (x/9) miles
Emily (x/8.25) miles
That is (16+x)/9=x/8.25
9x=132 +8.25 x
0.75 x=132
x=176 minutes
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With mph
Janine runs 60/9 mph and runs (16/60)hrs more than Emily, who runs at 60/8.25 mph.
{60/9}x+(16/60)*(60/9)=(60/8.25)x. They catch each other after x hours
(60/9)x+(16/9)=60/8.25)x
(60x+16)/9=60x/8.25
cross-multiply
495x+132=540x
45x=132
x=2.93 hours=176 minutes, rounding at end.
In 176 minutes, Janine will have run 192 minutes, and at 9 minutes a mile, that is 21 1/3 miles
In 176 minutes, Emily will have run, at 8.25 minutes per mile, 21 1/3 miles
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website! Janene and Emily plan to go on a marathon rn. Emily arrived late, So janene starts running 16 minutes before Emily. Janene runs at an average rate of 9 minutes per mile, and emily runs at the average rate of 8.25 minutes per mile. If they both start at the same location, how many minutes will it take for Emily to catch up to Janene?
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