SOLUTION: a rectangle is formed by increasing one side fo the square by 5cm and reducing the adjacent side of the square by 3cm. if the perimeter of the rectangle is 40cm find the length of

Algebra ->  Rectangles -> SOLUTION: a rectangle is formed by increasing one side fo the square by 5cm and reducing the adjacent side of the square by 3cm. if the perimeter of the rectangle is 40cm find the length of       Log On


   

Question 1043779: a rectangle is formed by increasing one side fo the square by 5cm and reducing the adjacent side of the square by 3cm. if the perimeter of the rectangle is 40cm find the length of the squares side.
Please help me solve this. Thank you!

Found 3 solutions by josgarithmetic, blupooth, MathTherapy:
Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
Put the whole description into an equation starting with some variable for the side of the square.

x, the side of original square.

The sides for the rectangle formed, (x+5) and (x-3);
2%28x%2B5%29%2B2%28x-3%29=40

Answer by blupooth(1) About Me  (Show Source):
You can put this solution on YOUR website!
2(x+5)+2(x-3)=40
=2x+10+2x-6=40
=4x+6=40
4x=34
x=34%2F4
x=8.5
:)

Answer by MathTherapy(10549) About Me  (Show Source):
You can put this solution on YOUR website!

a rectangle is formed by increasing one side fo the square by 5cm and reducing the adjacent side of the square by 3cm. if the perimeter of the rectangle is 40cm find the length of the squares side.
Please help me solve this. Thank you!
One side of square: highlight_green%28matrix%281%2C2%2C+9%2C+cm%29%29