SOLUTION: P(-5, 5) is a point on the terminal side of θ in standard position. What is the exact value of sec θ?

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Question 1043629: P(-5, 5) is a point on the terminal side of θ in standard position. What is the exact value of sec θ?
Answer by Alan3354(69443) About Me  (Show Source):
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P(-5,5) is a point on the terminal side of θ in standard position. What is the exact value of sec θ?
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r = sqrt(x^2 + y^2) = 5sqrt(2)
sec = r/x = -sqrt(2) (negative in Q2)