SOLUTION: Find the area of a square whose side is 18 cm and the dimension of rectangle whose length is twice the width and it's area is 128sq cm. 1. Area of square 2. Dimension of the rec

Algebra ->  Rectangles -> SOLUTION: Find the area of a square whose side is 18 cm and the dimension of rectangle whose length is twice the width and it's area is 128sq cm. 1. Area of square 2. Dimension of the rec      Log On


   



Question 1043566: Find the area of a square whose side is 18 cm and the dimension of rectangle whose length is twice the width and it's area is 128sq cm.
1. Area of square
2. Dimension of the rectangle
3. Which has the greater area
4. How much greater
5. Ratio of the area of square to rectangle

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
1.
AREA++OF++SQUARE+=+S%2AS+
AREA++OF++SQUARE+=+18%2A18+
AREA++OF++SQUARE+=+324+
2.
AREA+OF+RECTANGLE+=+L%2AW+
Lenght=2%2AWidht
AREA+OF+RECTANGLE+=+L%2AW+
128=+2%2AW%2AW+
64=+W%2AW+
64=+W%5E2+
8=+W+
l=+2%2A8+
L=+16+
3.Square
4.it is greater by 324-128=196+
5.ratio+Area+of+square%2Farea+of+rectangle=324%2F128=81%2F32
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