SOLUTION: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?
n^2+n-210=0
n^2+n-105=0
2n^2+2n+210=0
2n^2+2n+
Algebra ->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?
n^2+n-210=0
n^2+n-105=0
2n^2+2n+210=0
2n^2+2n+
Log On
Question 1043529: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?
n^2+n-210=0
n^2+n-105=0
2n^2+2n+210=0
2n^2+2n+105=0 Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?
n^2+n-210=0 <<<--- This one
n^2+n-105=0
2n^2+2n+210=0
2n^2+2n+105=0