SOLUTION: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers? n^2+n-210=0 n^2+n-105=0 2n^2+2n+210=0 2n^2+2n+

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers? n^2+n-210=0 n^2+n-105=0 2n^2+2n+210=0 2n^2+2n+      Log On


   



Question 1043529: Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?
n^2+n-210=0
n^2+n-105=0
2n^2+2n+210=0
2n^2+2n+105=0

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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Half of the product of two consecutive numbers is 105. Which equation can be used to solve for n, the smaller of the two numbers?

n^2+n-210=0     <<<--- This one

n^2+n-105=0

2n^2+2n+210=0

2n^2+2n+105=0