SOLUTION: hi tutors..thanks for all your help.How do I solve log base of 125^1/5 (5^3)^x=1/5 5^3x=1/5 then i used base 5 to each side logbase5(5^3x+log base5(1/5) then i did 3x=1 then

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: hi tutors..thanks for all your help.How do I solve log base of 125^1/5 (5^3)^x=1/5 5^3x=1/5 then i used base 5 to each side logbase5(5^3x+log base5(1/5) then i did 3x=1 then       Log On


   

Question 1043528: hi tutors..thanks for all your help.How do I solve log base of 125^1/5
(5^3)^x=1/5
5^3x=1/5
then i used base 5 to each side
logbase5(5^3x+log base5(1/5)
then i did 3x=1
then x=1/3
but my book says -1/3
can i have a detail account where i got this wrong
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve log base of 125^1/5
log%28125%2C%281%2F5%29%29 = y
exponent equiv
125%5Ey = 1%2F5
1/5 can be written as
125%5Ey = 5%5E-1
125 is five cubed
5%5E%283y%29 = 5%5E-1
therefore
3y = -1
y = -1%2F3