Question 1043501: Find the coefficient of b^16 in the binomial expansion of
(2b^3- 1/(4b^2))^12 Found 3 solutions by Boreal, Edwin McCravy, MathTherapy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! I am writing this as (2b^3-(1/4)b^2)
The first term will never be b^16, only the second term, and that is when it is raised to the 8th power.
That occurs at the binomial expansion 12C8 (2b^3)^4-(4b^2)^8=495{16b^12+(1/65536)b^16).
The (R-1)st term is
Remove the parentheses in the second factor by
multiplying exponents. Write 4 as 22
Write the factors in the denominator out of the
denominator with negative exponents:
Remove the parentheses by multiplying exponents:
Add the exponents of 2 and add the exponents of b:
Combine terms in the exponents:
Since we want the term in b16, we
set the exponent of b equal to 16
4R-24 = 16
4R = 40
R = 10
Coefficient of b16 = 4224
Edwin