Question 1043334: Suppose Grant is going to burn a compact disk (CD) that will contain 9 songs. In how many ways can Grant arrange the 9 songs on the CD?
Found 4 solutions by stanbon, addingup, ikleyn, MathTherapy:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose Grant is going to burn a compact disk (CD) that will contain 9 songs. In how many ways can Grant arrange the 9 songs on the CD?
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arrangements are permutations::
Ans: 9P9 = 9!/(9-9)! = 9!/0! = 9!= 362880
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Cheers,
Stan H,
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Answer by addingup(3677)  (Show Source):
You can put this solution on YOUR website! In general, n songs (or any object) can be arranged in n! ways.
In your case:
Once you burn the first song you have 8 songs to arrange
When you burn the second song you have 7 songs to arrange.
etc.
So, we use n! which means that your answer is:
9*8*7*6*5*4*3*2*1 your calculator may have a key for n!, mine does and when I do 9! it gives me 5,040 ways you can arrange the songs (the power of the multiplier).
Happy learning,
John
Answer by ikleyn(52818)  (Show Source):
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
Suppose Grant is going to burn a compact disk (CD) that will contain 9 songs. In how many ways can Grant arrange the 9 songs on the CD?
Use permutation, or 
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