SOLUTION: if sin x=3/5,pi/2 < x < pi, then find the value of cos x,tan x,sec x and cot x

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Question 1043325: if sin x=3/5,pi/2 < x < pi, then find the value of cos x,tan x,sec x and cot x
Answer by ikleyn(52781) About Me  (Show Source):
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if sin x=3/5,pi/2 < x < pi, then find the value of cos x,tan x,sec x and cot x
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cos(x) = -sqrt%281+-+sin%5E2%28x%29%29 = -sqrt%281-%283%2F5%29%29 = -sqrt%281+-+9%2F25%29 = -sqrt%28%2825-9%29%2F25%29 = -sqrt%2816%2F25%29 = -4%2F5%29.

The sign "-" before the square root is because  pi/2 < x < pi  and cosine is negative in QII.

Now, knowing sin(x) and cos(x), you can easily calculate the remaining functions on your own.

For similar problems, and to extend your knowledge, see the lessons
    - Calculating trigonometric functions of angles
    - Advanced problems on calculating trigonometric functions of angles
in this site.