SOLUTION: A rotating beacon is located a distance d from a long wall. The distance d is given by d = 3 tan 2πt, where t is the time measured in seconds since the beacon started rotati

Algebra ->  Trigonometry-basics -> SOLUTION: A rotating beacon is located a distance d from a long wall. The distance d is given by d = 3 tan 2πt, where t is the time measured in seconds since the beacon started rotati      Log On


   



Question 1043275: A rotating beacon is located a distance d from a long wall. The distance d is given by
d = 3 tan 2πt,
where t is the time measured in seconds since the beacon started rotating. Solve the equation for t.

Found 2 solutions by stanbon, ikleyn:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
d = 3 tan 2πt,
where t is the time measured in seconds since the beacon started rotating. Solve the equation for t.
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tan(2pit) = d/3
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2*pi*t = invtan(d/3)
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t = (1/(2pi))*invtan(d/3)
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Cheers,
Stan H.
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Answer by ikleyn(52835) About Me  (Show Source):
You can put this solution on YOUR website!
.
It seems to me that the problem in whole doesn't make sense.

There is no connection between the formula and rotating beacon. (and rotating at all).