Since 5C3 is only 10, we will just list them all,
add them and count the number of different sums
of weights:
1. 1+2+3 = 6
2. 1+2+4 = 7
3. 1+2+5 = 8
4. 1+3+4 = 8
5. 1+3+5 = 8
6. 1+4+5 = 10
7. 2+3+4 = 9
9. 2+3+5 = 10
9. 2+4+5 = 11
10. 3+4+5 = 12
So there are 7 different sums of weights,
{6,7,8,9,10,11,12}
Edwin