SOLUTION: Given that the gradient of a curve is 3x^2-4 and that the curve passes through (-1,6), determine the equation of the curve.

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Question 1043071: Given that the gradient of a curve is 3x^2-4 and that the curve passes through (-1,6), determine the equation of the curve.
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
Gradient is just another word for the slope of a tangent to a curve on one of its points. Let y = f(x).
===> dy%2Fdx+=+3x%5E2-4+ ===> y+=+x%5E3+-+4x+%2Bc for some undetermined coefficient c.
Since (-1, 6) is a point on the curve,
===> 6+=+%28-1%29%5E3+-+4%28-1%29+%2Bc ===> 6 = -1+4+c ===> c = 3.
Therefore the equation of the curve is highlight%28y+=+x%5E3+-+4x+%2B3%29.