SOLUTION: Having a really hard time with this questions. It asks to solve 100(1.02)^x/4=200. Could you please show the steps so I can understand it?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Having a really hard time with this questions. It asks to solve 100(1.02)^x/4=200. Could you please show the steps so I can understand it?       Log On


   

Question 1043030: Having a really hard time with this questions. It asks to solve 100(1.02)^x/4=200. Could you please show the steps so I can understand it?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
solve 100(1.02)^x/4=200
Assume you mean
solve 100%281.02%29%5E%28x%2F4%29+=+200
divide both sides by 100
%281.02%29%5E%28x%2F4%29+=+2
using nat logs
ln%281.02%29%5E%28x%2F4%29%29 = ln%282%29
the log equiv of exponents
x%2F4ln(1.02) = ln(2)
divide both sides by ln(1.02)
x%2F4 = ln%282%29%2Fln%281.02%29
using your calc
x%2F4 = 35.0028
multiply both sides by 4
x = 140
:
:
replace x with 140 in the original problem, check with your calc