SOLUTION: Solve for x on the interval [0,2pi].
cos^2(x)+3cos(x)+2=0
Someone please help, this assignment is due tomorrow and I cannot find how to do this anywhere.
Algebra ->
Trigonometry-basics
-> SOLUTION: Solve for x on the interval [0,2pi].
cos^2(x)+3cos(x)+2=0
Someone please help, this assignment is due tomorrow and I cannot find how to do this anywhere.
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Factor left side
(cos(x) + 1)*(cos(x) + 2) = 0.
Then the original equation deploys in two separate independent equations
1. cos(x) + 1 = 0 ---> cos(x) = -1 ---> x = , and
2. cos(x) + 2 = 0 ---> cos(x) = -2, which has no solutions.
Answer. x = .
