Question 1042922: A pile of 55 coins consisting of nickels and dimes is worth $3.90 . Find the number of each. Found 2 solutions by Fombitz, rothauserc:Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! let x be the number of nickels and y be the number of dimes
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we have the following two equations in two unknowns
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1) x + y = 55
2) .05x + .10y = 3.90
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solve equation 1) for x and substitute for x in equation 2)
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x = 55 - y
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.05(55 - y) + .10y = 3.90
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2.75 - .05y + .10y = 3.90
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.05y = 1.15
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y = 23
x = 32
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we have 32 nickels and 23 dimes
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we check this by substituting for x and y in equation 2)
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.05(32) + .10(23) = 3.90
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1.60 + 2.30 = 3.90
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3.90 = 3.90
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our answer checks :-)