SOLUTION: At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not d
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Question 1042908: At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ? Found 3 solutions by ikleyn, macston, MathTherapy:Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas ,
a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x - 3 = ,
x - 3 = ,
x - 3 = = ,
= ---> x = 60*3 = 180.
Answer. 180 guests.
You can put this solution on YOUR website! .
x=number of guests
.
0.25x+0.3333x+0.4x+3=x
0.9833x+3=x
3=0.0100x
300=x
.
ANSWER: There were 300 guests.
.
You can put this solution on YOUR website!
At a party, colas , squash and fruit juice were offered to guests. A fourth of the guests drank colas , a third drank squash , two fifths drank fruit juice and just three did not drink anything. How many guests were there in all ?
Let number of guests be G
Then:
15G + 20G + 24G + 180 = 60G -------- Multiplying by LCD, 60
59G + 180 = 60G
180 = 60G - 59G
G, or number of guests =
